College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.8 - Function Operations and Composition - 2.8 Exercises - Page 266: 8

Answer

$\left( \dfrac{f}{g} \right)(5)=-7$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given expression, $ \left( \dfrac{f}{g} \right)(5) ,$ given \begin{array}{l}\require{cancel} f(x)=x^2+3 \\ g(x)=-2x+6 ,\end{array} use the definition of the appropriate function operation. Then substitute $x$ with $ 5 .$ $\bf{\text{Solution Details:}}$ Since $\left( \dfrac{f}{g} \right)(x)=\dfrac{f(x)}{g(x)},$ then \begin{array}{l}\require{cancel} \left( \dfrac{f}{g} \right)(x)=\dfrac{x^2+3}{-2x+6} .\end{array} Substituting $x$ with $ 5 ,$ then \begin{array}{l}\require{cancel} \left( \dfrac{f}{g} \right)(5)=\dfrac{(5)^2+3}{-2(5)+6} \\\\ \left( \dfrac{f}{g} \right)(5)=\dfrac{25+3}{-10+6} \\\\ \left( \dfrac{f}{g} \right)(5)=\dfrac{28}{-4} \\\\ \left( \dfrac{f}{g} \right)(5)=-7 .\end{array}
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