# Chapter 2 - Section 2.7 - Graphing Techniques - 2.7 Exercises - Page 256: 68

See the picture below.

#### Work Step by Step

By calculating the values of $f(x)=\sqrt{x}-2$ (with blue) and $g(x)=\sqrt{x}$ (with red) we can see that the value of $f(x)$ is 2 less, than $g(x)$ for each corresponding x. In order to graph the exact parent graph, here is the table of values: $g(0)=\sqrt0=0$ $g(1)=\sqrt1=1$ $g(2)=\sqrt2=\sqrt2$ $g(3)=\sqrt3=\sqrt3$ $g(4)=\sqrt4=2$ (The square root function is not defined for negative numbers.) Therefore the graph of $f(x)$ is exactly the same as the graph of $g(x)=\sqrt{x}$ but is translated 2 units down.

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