College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.5 - Equations of Lines and Linear Models - 2.5 Exercises - Page 229: 67

Answer

(a) $x=12$ (b) Use an interval beyond $[-10,10]$ to include 12.

Work Step by Step

(a) We solve: $-2(x-5)=-x-2$ $-2x+10=-x-2$ $10=x-2$ $x=10+2$ $x=12$ (b) Most standard viewing windows span the interval $[-10,10]$, outside of the solution. We must use an interval around $12$, e.g. $[8,15]$.
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