Answer
(a) slope$=-2$
(b) $y=-2x+1$
Work Step by Step
(a)
We find the $x$-intercept by looking at the graph for the point at which $y=0$. Similarly, we find the $y$-intercept by looking for the point at which $x=0$.
y-intercept=$(0,1)$
x-intercept=$(\displaystyle \frac{1}{2},0)$
To calculate the slope between points $(x_1,y_1)$ and $(x_2,y_2)$, we use the formula:
$slope=m=\frac{y_2-y_1}{x_2-x_1}$
We plug in the $x$ and $y$ intercept points:
slope=$\frac{0-1}{1/2-0}=-2$
(b)
A line in slope-intercept has the form:
$y=mx+b$ ($m=slope$, $b=y-intercept$)
We plug in $m$ and $b$ from part (a):
$y=-2x+1$