College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.5 - Equations of Lines and Linear Models - 2.5 Exercises - Page 226: 23

Answer

$y=-4x-3$

Work Step by Step

Using $y-y_1=m(x-x_1)$ or the Point-Slope Form of linear equations, the equation of the line passing through $( -2,5 )$ and with slope, $m= -4 ,$ is \begin{array}{l}\require{cancel} y-5=-4(x-(-2)) \\\\ y-5=-4(x+2) \\\\ y-5=-4x-8 \\\\ y=-4x-8+5 \\\\ y=-4x-3 .\end{array}
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