College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.4 - Linear Functions - 2.4 Exercises - Page 213: 65

Answer

Rate of change=-4 The value of the machine must be decreasing at a rate of $4000 per year.

Work Step by Step

To calculate the rate of change between two points $(a,f(a))$ and $(b,f(b))$, where $b \gt a$, we use the formula: rate of change$=\frac{f(b)-f(a)}{b-a}$ We use the two points $(0,20)$ and $(4,4)$: rate of change$=\frac{4-20}{4-0}=\frac{-16}{4}=-4$ Thus the value of the machine must be decreasing at a rate of $4000 per year.
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