College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.4 - Linear Equations - 2.4 Exercises - Page 212: 35

Answer

$m=\dfrac{2}{5}$

Work Step by Step

Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope of the line passing through the given points $( 2,-1 )$ and $( -3,-3 )$ is \begin{array}{l}\require{cancel} m=\dfrac{-1-(-3)}{2-(-3)} \\\\ m=\dfrac{-1+3}{2+3} \\\\ m=\dfrac{2}{5} .\end{array}
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