Answer
$$d=((x_{2}-x_{1})^2+(y_{2}-y_{1})^2)^\frac{1}{2})$$
Work Step by Step
$$\sqrt{x}=x^\frac{1}{2}$$
$$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$$
$$d=((x_{2}-x_{1})^2+(y_{2}-y_{1})^2)^\frac{1}{2})$$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 2 - Section 2.1 - Rectangular Coordinates and Graphs - 2.1 Exercises - Page 180: 42
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