College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.1 - Rectangular Coordinates and Graphs - 2.1 Exercises - Page 179: 34

Answer

$(-2,7)$

Work Step by Step

Let $(m,n)$ be the missing endpoint. Using $\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$ or the Midpoint Formula, then the coordinates of the missing endpoint, given that the midpoint is $( -9,8 )$ and the other endpoint is $( -16,9 )$ are \begin{array}{l}\require{cancel} \dfrac{m+(-16)}{2}=-9 \\\text{AND}\\ \dfrac{n+9}{2}=8 .\end{array} Solving these equations separately results to \begin{array}{l}\require{cancel} m-16=2(-9) \\\\ m-16=-18 \\\\ m=-18+16 \\\\ m=-2 \\\text{AND}\\ n+9=2(8) \\\\ n+9=16 \\\\ n=16-9 \\\\ n=7 .\end{array} Hence, the missing endpoint is $ (-2,7) .$
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