College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Quiz - Sections 2.1-2.4 - Page 216: 2

Answer

Enrollment in 2002 was about 6.25 million. Enrollment in 2006 was about 6.76 million.

Work Step by Step

To find the midpoint between points $(x_1,y_1)$ and $(x_2,y_2)$, we use the midpoint formula: $\displaystyle Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ To estimate enrollment in 2002, we find the midpoint between $(2000,5.95)$ and $(2004,6.55)$: $Midpoint=(\frac{2000+2004}{2},\frac{5.95+6.55}{2})$ $=(2002,6.25)$ Thus enrollment in 2002 must have been around 6.25 million. Similarly, we estimate enrollment in 2006: $Midpoint=(\frac{2004+2008}{2},\frac{6.55+6.97}{2})$ $=(2006,6.76)$ Thus enrollment in 2006 was around 6.76 million.
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