College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.8 - Absolute Value Equations and Inequalities - 1.8 Exercises - Page 155: 80


All real numbers except $-\frac{7}{8}$.

Work Step by Step

We are given: $|\displaystyle \frac{9-x}{7+8x}|\geq 0$ We can see right away that this equation is almost always true because an absolute value is always positive or 0: $|x|\geq0$ for all $x$ However, we must make sure the denominator is not 0: $7+8x\ne 0$ $8x\ne -7$ $x\ne -\frac{7}{8}$ Thus the solution is all real numbers except $-\frac{7}{8}$.
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