Answer
$\displaystyle x=\frac{4}{3}$ or $x=-2$ or $x=-6$
Work Step by Step
We solve:
$(3x-4)(x+2)(x+6)=0$
Equate each factor to zero:
$(3x-4)=0$ or $(x+2)=0$ or $(x+6)=0$
We solve for $x$ in each equation:
$3x=4$ or $x=-2$ or $x=-6$
$\displaystyle x=\frac{4}{3}$ or $x=-2$ or $x=-6$
