College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.6 - Other Types of Equations and Applications - 1.6 Exercises - Page 133: 4

Answer

$$x\ne -3, 1$$

Work Step by Step

The denominator cannot equal zero; none of the quadratics in the denominator can be equal to zero. $$x+3\ne 0$$ $$x\ne -3$$ $$x-1\ne 0$$ $$x\ne 1$$ $$x^2+2x-3\ne 0$$ $$(x+3)(x-1)\ne 0$$ $$x\ne -3, 1$$
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