College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.5 - Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 119: 7

Answer

The first pair of integers is 12 and 14. The second pair is -14 and -12.

Work Step by Step

$$x(x+2)=168$$ $$x^2+2x=168$$ $$x^2+2x-168$$ $$(x+14)(x-12)=0$$ $$x=12,-14$$ The first pair of integers is 12 and 14. The second pair is -14 and -12.
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