## College Algebra (11th Edition)

$-\frac{1}{8}+\frac{\sqrt{2}}{8}i$
Original Problem: $\frac{-3 + \sqrt{-18}}{24}$ Factor out $\sqrt{-1}$ and 3 from $\sqrt{-18}$. $\frac{-3+3\times\sqrt{-1}\times\sqrt{2}}{24}$ Recall that $\sqrt{-1}$ = $i$. $\frac{-3+3i\sqrt{2}}{24}$ Simplify. $\frac{-1+i\sqrt{2}}{8}$ Separate. $-\frac{1}{8}+\frac{\sqrt{2}}{8}i$