College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Review Exercises - Page 165: 105


$x=3$ would cause division by 0.

Work Step by Step

$x=3$ can not be a solution to $|\frac{14x+9}{x-3}|<0$ because it causes division by 0 in the denominator (which is undefined).
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