College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Polynomials - R.4 Assess Your Understanding: 87

Answer

$x^3-6x^2+12x-8$

Work Step by Step

$(x-2)^3$ The cube of the difference of two terms is written as: $a^3 – 3a^2b + 3ab^2 – b^3$ After substituting: $x^3-3(x^2*2)+3(x)(2)^2-(2)^3=$ $x^3-6x^2+12x-8$
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