## College Algebra (10th Edition)

$x^3-6x^2+12x-8$
$(x-2)^3$ The cube of the difference of two terms is written as: $a^3 – 3a^2b + 3ab^2 – b^3$ After substituting: $x^3-3(x^2*2)+3(x)(2)^2-(2)^3=$ $x^3-6x^2+12x-8$