## College Algebra (10th Edition)

$\frac{3}{2}$
$-3x^{-1}y$ if x=2, and y = -1. Substitute the values: Remember that to make an exponent positive, take the reciprocal of its base and then apply the opposite of the previous exponent to the denominator. $-3(2)^{-1}*-1$ $-3*\frac{1}{2^{1}}*-1.$ Therefore, the answer is: $\frac{3}{2}$