Answer
See below.
Work Step by Step
Assume for $n=k$: $2+4+6+...+2k=k^2+k+2$.
Then for $n=k+1$: $2+4+6+...+2k+2(k+1)=k^2+k+2+2(k+1)=k^2+3k+4=k^2+2k+1+(k+1)+2=(k+1)^2+(k+1)+2$. Thus we proved what we wanted to.
For $n=1:2\ne1^2+1+2=4$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Section 9.4 - Mathematical Induction - 9.4 Assess Your Understanding - Page 670: 29
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