College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.3 - Geometric Sequences; Geometric Series - 9.3 Assess Your Understanding - Page 665: 85

Answer

${{\$}} 47,271.37$

Work Step by Step

Increasing x by $ 3\%$ is multiplying it with $1+0.03=1.03.$ $a_{1}=42,000$ $a_{2}=42,000(1.03)$ $a_{3}=42,000(1.03)^{2}...$ This is a geometric series with $a_{1}=42,000$, $r=1.03,\ \quad a_{n}=a_{1}r^{n-1}$ We want $a_{5}=42,000(1.03)^{4}\approx 47,271.37$
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