College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.1 - Sequences - 9.1 Assess Your Understanding - Page 649: 102

Answer

$A=2661.02$

Work Step by Step

$P=2500, r=3\%=0.03, n=12, t=2$ $A=P(1+\frac{r}{n})^{nt},$ $=2500(1+\frac{0.03}{12})^{24}=2500(1.0025)^{24}=2661.02$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.