## College Algebra (10th Edition)

We evaluate $z$ at the corner points: $(0,6):z=0+6=6$ $(5,6):z=5+6=11$ $(5,2):z=5+2=7$ $(4,0):z=4+0=0$ $(0,3):z=0+3=3$ Thus the maximum value is $11$, the minimum value is $3$.