College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.8 - Linear Programming - 8.8 Assess Your Understanding - Page 630: 3


See below.

Work Step by Step

We evaluate $z$ at the corner points: $(0,6):z=0+6=6$ $(5,6):z=5+6=11$ $(5,2):z=5+2=7$ $(4,0):z=4+0=0$ $(0,3):z=0+3=3$ Thus the maximum value is $11$, the minimum value is $3$.
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