## College Algebra (10th Edition)

$\frac{-3\pm\sqrt{65}}{7}$.
The quadratic formula is: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$. Hence the solutions are: $x=\frac{-6\pm\sqrt{6^2-4\cdot7(-8)}}{2\cdot7}=\frac{-6\pm\sqrt{36+224}}{14}=\frac{-6\pm\sqrt{260}}{14}=\frac{-3\pm\sqrt{65}}{7}$.