College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.6 - Systems of Nonlinear Equations - 8.6 Assess Your Understanding - Page 617: 102



Work Step by Step

The quadratic formula is: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$. Hence the solutions are: $x=\frac{-6\pm\sqrt{6^2-4\cdot7(-8)}}{2\cdot7}=\frac{-6\pm\sqrt{36+224}}{14}=\frac{-6\pm\sqrt{260}}{14}=\frac{-3\pm\sqrt{65}}{7}$.
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