Answer
$x=0$ or $x=-2/3$
and $y=1, y=-1/3$
Respectively
Work Step by Step
Plugging in the 1st equation to the 2nd gives us,
$2x^2+(2x+1)^2=1$
$6x^2+4x+1=1$
or $6x^2+4x=0$
x=0 or $x=-2/3$
and y=1, y=-1/3
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Section 8.6 - Systems of Nonlinear Equations - 8.6 Assess Your Understanding - Page 615: 27
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
