College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.4 - Matrix Algebra - 8.4 Assess Your Understanding - Page 599: 79

Answer

The system is inconsistent (has no solution). Solution set =$ \emptyset.$

Work Step by Step

Method: Gauss-Jordan. Row reduce the augmented matrix: $\left[\begin{array}{rrr|r} {5}&{-1}&{4}&{2}\\ {-1}&{5}&{-4}&{3}\\ {7}&{13}&{-4}&{17}\end{array}\right]\qquad\left\{\begin{array}{l} R_{1}=-r_{2}.\\ R_{2}=r_{1}.\\ . \end{array}\right\}\rightarrow$ $\rightarrow\left[\begin{array}{rrr|r} {1}&{-5}&{4}&{-3}\\ {5}&{-1}&{4}&{2}\\ {7}&{13}&{-4}&{17}\end{array}\right]\qquad\left\{\begin{array}{l} .\\ R_{2}=r_{2}-5r_{1}.\\ R_{3}=r_{3}-7r_{1}. \end{array}\right\}\rightarrow$ $\left[\begin{array}{ccc|c} {1}&{-5}&{4}&{-3}\\ {0}&{24}&{-16}&{17}\\ {0}&{48}&{-32}&{38}\end{array}\right]\qquad\left\{\begin{array}{l} .\\ .\\ R_{3}=r_{3}-2r_{2}. \end{array}\right\}\rightarrow$ $\left[\begin{array}{ccc|c} {1}&{-5}&{4}&{-3}\\ {0}&{24}&{-16}&{17}\\ {0}&{0}&{0}&{4}\end{array}\right]$ the last row represents the equation$ \quad 0=4,$ which is never satisfied. The system is inconsistent (has no solution). Solution set =$ \emptyset.$
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