Answer
$x=-5$
Work Step by Step
2 by 2 determinant: $D=\left|\begin{array}{ll}
a & b\\
c & d
\end{array}\right|=ad-bc$
---
$\left|\begin{array}{ll}{x}&{x}\\{4}&{3}\end{array}\right|=3x-4x=-x$,
so we are solving
$-x=5$
$x=-5$
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