College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.2 - Systems of Linear Equations: Matrices - 8.2 Assess Your Understanding - Page 572: 76

Answer

$y=x^2-4x+2$

Work Step by Step

$y=ax^2+bx+c,$ $(1,-1),(3,-1),(-2,14)$ $\begin{cases}a+b+c=-1\\ 9a+3b+c=-1\\ 4a-2b+c=14 \end{cases}$ Multiplying the first equation by $2$ and adding it to the third equation. $\begin{cases}2a+2b+2c=-2\\ 4a-2b+c=14\\ -- -- -- -- \\ 6a+3c=12 \end{cases}$ After simplifying the result becomes, $2a+c=4$ Multiplying the first equation by -3 and adding it to the second equation. $\begin{cases}-3a-3b-3c=3\\ 9a+3b+c=-1\\ -- -- -- --\\ 6a-2c=2, \end{cases}$ After simplifying the result becomes, $3a-c=1$ Adding the result together. $\begin{cases}2a+c=4\\ 3a-c=1\\ -- -- --\\ 5a=5 \end{cases}$ Thus, $a=1, b=-4, c=2.$ Therefore, $y=x^2-4x+2$
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