Answer
See below.
Work Step by Step
$2x^2+7x-4=6x+11\\2x^2+x-15=0\\(2x-5)(x+3)=0$
Thus $x=2.5$ (then $y=6\cdot2.5+11=26$) or $x=-3$ (then $y=6\cdot-3+11=-7$).
Thus the points are $(2.5,26)$ and $(-3,-7)$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 7 - Section 7.3 - The Ellipse - 7.3 Assess Your Understanding - Page 527: 92
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