Answer
$5$
Work Step by Step
We know that $a^b=a^c\longrightarrow b=c$ if $a\ne1,a\ne-1$ (which applies here).
Hence here $4^{x+1}=8^{x-1}\\(2^2)^{x+1}=(2^3)^{x-1}\\2^{2(x+1)}=2^{3(x-1)}\\2(x+1)=3(x-1)\\2x+2=3x-3\\2=x-3\\x=5$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 7 - Section 7.2 - The Parabola - 7.2 Assess Your Understanding - Page 516: 83
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