College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 7 - Section 7.2 - The Parabola - 7.2 Assess Your Understanding - Page 514: 3


The solution set is {$-7,-1$}

Work Step by Step

To find the real solutions of $(x+4)^2=9$ with the Square Root Method, we take the square root of both sides and then solve for x. $\sqrt{(x+4)^2}=\sqrt{9}$ $x+4=\pm3$ $x=-4\pm3$ Therefore, the solution set is {$-7,-1$}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.