Answer
Parabola.
Vertex: $\quad (0,1)$
Focus: $\quad (0,0)$
Directrix: $\quad y=2$
Work Step by Step
One variable is squared, the other is not: Parabola.
$x^{2}+4y=4$
$x^{2}=-4y+4$
$x^{2}=-4(y-1)$
$x^{2}=-4(1)(y-1)$
Table $2$:
$\begin{array}{lll}
{\text{Focus}}&{\text{Directrix}}&{\text{Equation}}\\\hline
{(h,k-a)}&{y=k+a}&{(x-h)^{2}=-4a(y-k)} \end{array}$
$a=1$
Vertex: $\quad (0,1)$
Focus: $\quad (h,k-a)=(0.1-1)=(0,0)$
Directrix: $\quad y=k+a\quad \Rightarrow\quad y=2$
