Answer
See below.
Work Step by Step
The Remainder Theorem says that the remainder of a function $f(x)$ after dividing by $(x-r)$ is $f(r)$.
Hence here the remainder is $f(1)=6(1)^{3}+3(1)^{2}+2(1)-11=6+3+2-11=0$. The remainder is $0$, thus $g$ is a factor of $f$.
