College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 449: 29



Work Step by Step

RECALL: $\log_a{(a^n)} = n, a \gt 0, a \ne1$ Since $25=5^2$, the given expression is equivalent to: $\log_5{(5^2)}$ Using the property above gives: $\log_5{(5^2)} = 2$ Thus, $\log_5{25} = 2$.
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