Chapter 6 - Section 6.2 - One-to-One Functions; Inverse Functions - 6.2 Assess Your Understanding - Page 421: 63

$f^{-1}(x)=\frac{2}{x}-3$

$f(x)=\frac{2}{3+x},$ $y=\frac{2}{3+x},$ a. $x=\frac{2}{3+y},$ $3+y=\frac{2}{x},$ $y=\frac{2}{x}-3=f^{-1}(x),$ b. Domain of $f(x)$ is $x\in \mathbb{R} \ne -3,$ and Domain of $f^{-1}(x)$ is $x\in \mathbb{R} \ne 0$