Answer
$f(g(x))=x$
$g(f(x))=x$
Work Step by Step
$f(x)=x^3-8,$ $g(x)=\sqrt[3] {x+8},$
$f(g(x))=(\sqrt[3] {x+8})^3-8=|x+8|-8=x$
Domain of $f\circ g(x)$ is $x\in \mathbb{R}$
$g(f(x))=\sqrt[3] {x^3-8+8}=\sqrt[3] {x^3}=|x|=x$
Domain of $g\circ f(x)$ is $x\in \mathbb{R}$