## College Algebra (10th Edition)

$6x^3-13x^2-13x+20$
Multiply each term of the binomial to trinomial to obtain: $=2x(3x^2+x-4)-5(3x^2+x-4)$ Distribute $2x$ and $-5$ to obtain: $=2x(3x^2) + 2x(x) - 2x(4) - 5(3x^2)-5(x)-5(-4) \\=6x^3+2x^2-8x-15x^2-5x+20$ Combine like terms to obtain: $=6x^3 + (2x^2-15x^2)+(-8x-5x)+20 \\=6x^3-13x^2-13x+20$