Answer
$y=2x-1$ is oblique asymptote.
No vertical asymptote
Work Step by Step
$R(x)=\frac{6x^2+7x-5}{3x+5}=\frac{(3x+5)(2x-1)}{3x+5}=2x-1, x\not=1/2,x=-5/3$
The degree of the leading coefficient of the numerator is, $n=3$. the degree of the leading coefficient the denominator is, $m=2$.
Thus, $n=m+1,$
When $n=m+1,$ the quotient of the division of numerator by denominator is Oblique asymptote.
$\begin{array} x &2x-1\\
&-- -- -- --\\
3x+5|& 6x^2+7x-5\\
& -6x^2-10x\\
& -- -- -- -- \\
& -3x-5\\
& 3x+5\\
&-- -- -- -- \\
& 0
\end{array}$
Thus, $y=2x-1$ is Oblique asymptote.
Factorizing the denominator,
$x=-\frac{5}{3},$
There is no vertical asymptote.
