## College Algebra (10th Edition)

It always contains the following points: $(-1, 1), (0,0), \text{and} (1,1)$.
Whenever x equals 0, y will always equal zero no matter what power x is raised to. Thus, $(0,0)$ is always a point on a graph of this function. Whenever x is one, y will be one no matter what n is, so $(1,1)$ is on the graph of $y=x^n$ no matter what. Finally, since we are given that n is even, $(-1, 1)$ will be on the graph, for -1 raised to any even power is equal to one.