College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 4 - Test - Page 318: 9

Answer

(a) $C(m)=0.15x+129.50$ (b) 258.5 dollars (c) 562 miles

Work Step by Step

(a) We can represent the exercise in the form y=mx+b, where m is the rate of change (0.15 dollars per mile) and b is the initial fixed price (129.50 dollars): $C(m)=0.15x+129.50$ (b) Calculate C(860): $C(m)=0.15(860)+129.50$ $C(m)=129+129.50$ $C(m)=258.5$ dollars (c) Replace 213.80 for C(x) and solve for x: $213.80=0.15x+129.50$ $213.80-129.50=0.15x+129.50-129.50$ $84.3=0.15x$ $84.3/0.15=0.15x0.15$ $x=562$ miles
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.