Answer
$\frac{-4\pm\sqrt{31}}{5}$.
Work Step by Step
The quadratic formula is: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$.
Hence the solutions are: $x=\frac{-8\pm\sqrt{8^2-4\cdot5(-3)}}{2\cdot5}=\frac{-8\pm\sqrt{64+60}}{10}=\frac{-4\pm\sqrt{31}}{5}$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 4 - Section 4.4 - Build Quadratic Models from Verbal Descriptions and From Data - 4.4 Assess Your Understanding - Page 311: 35
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