College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 4 - Section 4.3 - Quadratic Functions and Their Properties - 4.3 Assess Your Understanding - Page 302: 103


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Work Step by Step

$x^2+y^2-10x+4y+20=0\\(x-5)^2-25+(y+2)^2-4+20=0\\(x-5)^2+(y+2)^2=9=3^2$ The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$, hence here the center is $(5,-2)$ and the radius is $3.$
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