College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 4 - Review Exercises - Page 317: 19

Answer

$f(x)=-3(x-2)^2-4$.

Work Step by Step

If the vertex of a graph is at (m,n) then the general formula for the quadratic function is $f(x)=a(x-m)^2+n$. The vertex of the graph is at (2,-4), hence the quardatic function becomes $f(x)=a(x-2)^2-4$. The point (0,-16) is on the graph (because of the y-intercept), hence if we plug in the values we get -16=4a-4, hence a=-3, hence $f(x)=-3(x-2)^2-4$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.