College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Test - Page 270: 3

Answer

See below.

Work Step by Step

The term in the denominator must be non-zero, thus $|x+2|\ne0\\x+2\ne0\\x\ne-2$ Thus the domain is the real numbers except $-2$. $f(-1)=\frac{-1+2}{|-1+2|}=\frac{1}{1}=1$
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