College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.6 - Mathematical Models: Building Functions - 3.6 Assess Your Understanding - Page 264: 18

Answer

See below.

Work Step by Step

One of them will be $30t$, the other one will be $40t$ from the junction and these routes are perpendicular to each other, thus by Pythagorean's theorem: $d(t)=\sqrt{(30t)^2+(40t)^2}=\sqrt{900t^2+1600t^2}=\sqrt{2500t^2}=50t$
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