Answer
$\frac{9x-x^3}{2}$
Work Step by Step
Area of right triangle: $length*width/2$. $y=9-x^2$, thus the width of the right triangle is $x$, the length is $9-x^2$, thus its area is: $x\cdot (9-x^2)=\frac{9x-x^3}{2}$
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