## College Algebra (10th Edition)

slope: $m=\displaystyle \frac{3}{5}$ $\mathrm{y}$-intercept: $b=-6$
$3x-5y=30$ We solve for $y$: $-5y=30-3x$ $y=\frac{3}{5}x-6$ Since the line now has the form $y=mx+b$, we see that the slope is $m=\displaystyle \frac{3}{5}$ and the $\mathrm{y}$-intercept is $b=-6.$