Answer
$f(x)=(x-3)^2-9$
Work Step by Step
Completing the square:
$f(x)=x^2-6x$
$f(x)=x^2-6x+(\frac{6}{2})^2-(\frac{6}{2})^2$
$f(x)=x^2-6x+3^2-3^2$
$f(x)=(x-3)^2-9$
Graphing the function:
1st step (black graph): The parent function: $y=x^2$
2nd step (green graph): Shift down by 9 units. $y=x^2-9$
Final step (blue graph): Shift right by 3 units. $y=(x-3)^2-9$
