College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.4 - Library of Functions; Piecewise-defined Function - 3.4 Assess Your Understanding - Page 247: 73

Answer

See below.

Work Step by Step

$x^2+y^2=6y+16\\x^2+y^2-6y-16=0\\x^2+(y-3)^2-9-16\\x^2+(y-3)^2=25=5^2$ The general equation for a circle with radius $r$ and center $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$, hence here the center is: $(0,3)$ and the radius is $5$.
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