## College Algebra (10th Edition)

$\color{blue}{y+2=5(x-3)}$
RECALL: The point-slope form of a line's equation is: $y-y_1=m(x-x_1)$ where $m$ = slope and the point $(x_1, y_1)$ is on the line. The given line has a slope of $5$ and contains the point $(3, -2)$. Substitute these values into the point-slope form equation to obtain: $y-(-2) = 5(x-3) \\\color{blue}{y+2=5(x-3)}$