Answer
$y=\frac{2}{3}x+8$
Work Step by Step
We find a line with a slope of $2/3$ that passes through $(-6,4)$ using the point-slope form:
$y-y_{1}=m(x-x_{1})$
$y-4=\displaystyle \frac{2}{3}(x- -6)$
$y-4=\displaystyle \frac{2}{3}(x+6)$
$y-4=\frac{2}{3}x+4$
$y=\frac{2}{3}x+8$